{"@type":"type.googleapis.com/h5game.http.service.v1.GetGameInfoResponse","id":37233,"likes_count":619,"icon":"https://static.17yoo.cn/h5_game/yingyongbao/wx56255ae87c45ac28/e55b46296e48f93a67d747c9b85e6ffd.png","cover_url":"","video_url":"","name":"方块箭头消","description":"第10关至今零通关！你能成为破局第一人吗？","categories":[32],"type":2,"url":"","screenshots":[],"like":false,"keywords":[],"short_description":"第10关至今零通关！你能成为破局第一人吗？","diagram":"","source":9,"article":null,"rank_enable":false,"game_id":32419,"rank_type":1,"pause_ad_enable":true,"corner_mark":0,"suitable_age":"","studio":"应用宝","source_jump_type":2,"recommend_enable":false,"recommend_game":[],"iframe_code":"","game_model":0,"social_game_type":0,"categories_detail":[{"id":32,"name":"微信小游戏","introduction":""}],"qq_appid":"","topics":[],"score":1,"cloud_config_enable":false,"tags":[],"game_code":"wx56255ae87c45ac28","adapted_platforms":[1],"operation_desc":"","operation_desc_enable":false,"ad_slot":"{}","seo_description":"","long_description":"<h2>方块箭头消游戏说明</h2>\n<p>方块箭头消是一款烧脑益智休闲游戏，上线至今第10关无人通关，全网等待破局第一人。玩家需巧妙利用箭头方块规则，消除障碍达成通关目标，快来挑战这场益智极限对决。</p>\n\n<h2>如何在线玩方块箭头消</h2>\n<p>在<a href='https://www.17yoo.cn/'>17yoo</a>平台搜索方块箭头消即可在线免费玩，无需下载。打开网页就能开启闯关之旅，随时挑战那座无人登顶的第10关，向着破局第一人发起冲击。</p>\n\n<h2>游戏玩法</h2>\n<p>跟随以下步骤开启方块箭头消挑战：\n<ol>\n<li><strong>观察布局：</strong>开局先看清箭头方块与普通方块的分布，预判消除连锁反应。</li>\n<li><strong>选择起点：</strong>点击带有箭头的方块，触发箭头指向的消除路径。</li>\n<li><strong>连锁消除：</strong>利用箭头传递消除效果，逐步清空屏幕方块完成通关。</li>\n</ol></p>\n\n<h2>方块箭头消怎么操作</h2>\n<p>方块箭头消操作简单易上手，全程点击屏幕即可完成。点击箭头方块触发消除指令，根据箭头方向自动消除对应路径方块，失误时可刷新重开，轻松开启新一轮益智挑战。</p>\n\n<h2>游戏特色</h2>\n<p>方块箭头消凭借独特亮点收获超高关注：\n<ul>\n<li><strong>零通关关卡：</strong>第10关至今无人通关，打造全网热议的益智谜题。</li>\n<li><strong>极简画风：</strong>清新简约的方块界面，专注闯关无需多余视觉干扰。</li>\n<li><strong>随时畅玩：</strong>无时长限制，利用碎片化时间就能开启烧脑对决。</li>\n</ul></p>\n\n<h2>玩方块箭头消有哪些游戏益处</h2>\n<p>玩方块箭头消能锻炼逻辑推理能力，通过预判消除路径提升思维敏捷度。闯关过程还能舒缓日常压力，在烧脑挑战中获得成就感，让休闲时光兼具娱乐与益智双重价值。</p>\n\n<h2>总结</h2>\n<p>方块箭头消是17yoo平台超火的益智休闲小游戏，第10关的零通关传说等待你打破。快来17yoo搜索方块箭头消，开启烧脑闯关，争当全网破局第一人，解锁专属益智荣耀。</p>","image_vertical":"","is_off":false}